/**數(shù)組根據(jù)數(shù)組對(duì)象中的某個(gè)屬性值進(jìn)行排序的方法   * 使用例子：newArray.sort(sortByArr(['number'],false)) //表示根據(jù)number屬性降序排列;若第二個(gè)參數(shù)不傳遞，默認(rèn)表示升序排序  * @param attr 排序的屬性 ['name','sex'...],根據(jù)一個(gè)字段或者多個(gè)字段排序  * @param rev true表示升序排列，false降序排序  * */function sortByArr(arr, rev) { if (rev == undefined) { rev = 1; } else { rev = (rev) ? 1 : -1; } return function(a, b) { for (var i = 0; i < arr.length; i++) { let attr = arr[i] if (a[attr] != b[attr]) { if (a[attr] > b[attr]) { return rev * 1; } else { return rev * -1; } } }}}

var persons = [  {name: "tina", age: 14},  {name: "timo", age: 15},  {name: "lily", age: 16},  {name: "lucy", age: 16}]

//1. 獲取 name 等于 lily 的對(duì)象var lily = persons.filter((p) => {  return p.name == "lily";});console.log(lily); //打印結(jié)果 [{name: "lily", age: 16}]//注：filter()方法返回的是一個(gè)數(shù)組var twins = persons.filter((p) => {  return p.age == 16;});console.log(twins); //打印結(jié)果 [{name: "lily", age: 16},{name: "lucy", age: 16}]

//刪除 name 等于 tina 的對(duì)象，利用splice()方法//1. 首先我們要得到這個(gè)對(duì)象var tina = persons.filter((p) => {  return p.name == "tina";});//2. 其次得到這個(gè)對(duì)象在數(shù)組中對(duì)應(yīng)的索引var index = persons.indexOf(tina[0]);//3. 如果存在則將其刪除，index > -1 代表存在index > -1 && persons.splice(index, 1);console.log(persons);//打印結(jié)果 [{name: "timo", age: 15}, {name: "lily", age: 16}, {name: "lucy", age: 16}]

//將 name 等于 timo 的 age 修改為 20//1. 得到 timo 對(duì)象var timo = persons.filter((p) => {  return p.name == "timo";});//2. 修改agetimo[0].age = 20;

//這個(gè)最簡(jiǎn)單了persons.push({name: "similar", age: 18});