#include <stdio.h>
#include <stdlib.h>
#define N 10 //算N的階乘
int main()
{       //數(shù)組   1位 1!
    int ary[N] = {1, 1};
    int i, j;
    for (i = 2; i <= N; i++)
    {
        //各個(gè)下標(biāo)的階乘，第0位下標(biāo)是位數(shù)，所以從第1位開(kāi)始
        for (j = 1; j <= ary[0]; j++)
        {
            ary[j] = ary[j] * i;
        }
        //處理進(jìn)位問(wèn)題 1W就進(jìn)一位
        for (j = 1; j <= ary[0]; j++)
        {
            if (ary[j] >= 10000)
            {
                //進(jìn)位
                ary[j+1] = ary[j+1] + ary[j] / 10000;
                //進(jìn)位后就只留下余數(shù)
                ary[j] = ary[j] % 10000;
            }
        }
        //有進(jìn)位的話，位數(shù)就+1
        //這里j已經(jīng)是位數(shù)大于1了
        if (ary[j] >= 1)
        {
            ary[0]++;
        }
    }

    //倒序輸出
    for (j = ary[0]; j > 0; j--)
    {
        printf("%d", ary[j]);
    }
    printf("/r/n");
    return 0;
}