今天
select * from 表名 where to_days(時間字段名) = to_days(now());
昨天
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 時間字段名) <= 1
近7天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間字段名)
近30天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間字段名)
本月
SELECT * FROM 表名 WHERE DATE_FORMAT( 時間字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )
上一月
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 時間字段名, '%Y%m' ) ) =1
查詢本季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
查詢上季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
查詢本年數據
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
查詢上年數據
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
查詢當前這周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查詢上周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查詢上個月的數據
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')select * from user where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) select * from user where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) select * from user where pudate between 上月最后一天 and 下月第一天
查詢當前月份的數據
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查詢距離當前現在6個月的數據
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
PS:下面看下mysql/272038.html">mysql/31051.html">mysql如何查詢當天信息？
原來不是太熟悉SQL查詢語句，什么都是用到了再去查去找，還好網絡提供給我們很多支持。今天又用到了一個語句，一時間真想不出怎么解決，到網上看了看，感覺就有一個，怎么那么簡單啊。需要積累的東西真是太多了。
今天就把我這個簡單的問題記錄下來吧!算是一個積累：
mysql查詢當天的所有信息：
select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
這個有一些繁瑣，還有簡單的寫法：
select * from table where date(regdate) = curdate();
date()函數獲取日期部分, 扔掉時間部分，然后與當前日期比較即可
新聞熱點
疑難解答
