問題描述 給定當(dāng)前的時(shí)間,請用英文的讀法將它讀出來。 時(shí)間用時(shí)h和分m表示,在英文的讀法中,讀一個(gè)時(shí)間的方法是: 如果m為0,則將時(shí)讀出來,然后加上“o’clock”,如3:00讀作“three o’clock”。 如果m不為0,則將時(shí)讀出來,然后將分讀出來,如5:30讀作“five thirty”。 時(shí)和分的讀法使用的是英文數(shù)字的讀法,其中0~20讀作: 0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。 30讀作thirty,40讀作forty,50讀作fifty。 對于大于20小于60的數(shù)字,首先讀整十的數(shù),然后再加上個(gè)位數(shù)。如31首先讀30再加1的讀法,讀作“thirty one”。 按上面的規(guī)則21:54讀作“twenty one fifty four”,9:07讀作“nine seven”,0:15讀作“zero fifteen”。 輸入格式 輸入包含兩個(gè)非負(fù)整數(shù)h和m,表示時(shí)間的時(shí)和分。非零的數(shù)字前沒有前導(dǎo)0。h小于24,m小于60。 輸出格式 輸出時(shí)間時(shí)刻的英文。 樣例輸入 0 15 樣例輸出 zero fifteen 代碼分享:
#include<stdio.h>int main(){ int h; int mm; char hour[6][11]={" "," ","twenty","thirty","forty","fifty"};//整時(shí)刻如20 30 40的報(bào)時(shí)英文數(shù)字 char min[21][11]={"zero","one","two","three","four","five","six","seven","eight", "nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen", "seventeen","eighteen","nineteen","twenty"};//保存報(bào)時(shí)的英文數(shù)字 scanf("%d %d",&h,&mm); if(h>=0&&h<=20)新聞熱點(diǎn)
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