ASPCMS三級分類當(dāng)前樣式及其解決辦法

2024-04-25 20:47:41

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供稿：網(wǎng)友

<div>
        <ul><!– 一級和二級欄目，二級下拉菜單–！>
               <li><a href=”/”>網(wǎng)站首頁</a></li>
             {aspcms:navlist}
               <li><a href=”[navlist:link]“{if:[navlist:sortid]={aspcms:topsortid}} {end if}>[navlist:name]</a>
                        <ul>
                          {aspcms:subnavlist type=[navlist:sortid]}
                            <li><a href=”[subnavlist:link]“>[subnavlist:name]</a></li>
                          {/aspcms:subnavlist}
                    </ul>
               </li>
             {/aspcms:navlist}
       </ul>
</div>
    <!–二級及三級菜單–！>
                 <ul>
                    {aspcms:navlist type={aspcms:topsortid}}
                            <li><a href=”[navlist:link]” {if:[navlist:sortid]={aspcms:sortid}}{end if} {if:[navlist:sortid]={aspcms:parentsortid}}{end if}>[navlist:name]</a>
                             <ul>
                            {if:[navlist:sortid]={aspcms:parentsortid}}
                                {aspcms:subnavlist type=[navlist:sortid]}
                                 <li><a href=’[subnavlist:link]‘ id=’menu_[subnavlist:sortid]‘>[subnavlist:name]</a></li>
                                {/aspcms:subnavlist}
                            {end if}
                             </ul>
                     </li>
                    {/aspcms:navlist}
                </ul>
<script language=”javascript”>
              var d = document.getElementById(“menu_{aspcms:sortid}”);
                if(d != null){
                        d.className = “Txtnav2″;
                }
</script>

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