輸入一棵二叉樹,求該樹的深度。從根結(jié)點(diǎn)到葉結(jié)點(diǎn)依次經(jīng)過的結(jié)點(diǎn)(含根、葉結(jié)點(diǎn))形成樹的一條路徑,最長路徑的長度為樹的深度。
IDEA
DFS遍歷,左右遞歸返回左右子樹最長的
CODE
/**public class TreeNode { int val = 0; TreeNode left = null; TreeNode right = null; public TreeNode(int val) { this.val = val; }}*/public class Solution { public int TreeDepth(TreeNode root) { if(root==null){ return 0; } int num_left=TreeDepth(root.left); int num_right=TreeDepth(root.right); return num_left>num_right?(num_left+1):(num_right+1); }}
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