鉆石棋網頁游戲代碼

2024-09-05 12:20:58

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基于JavaScript+CSS共同完成的一款小型網頁游戲，鉆石棋，具體玩法還不太懂，你在網上搜搜玩法，應該比較有意思，一共有32個棋子。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=gb2312" /><title>鉆石棋游戲</title><style>body{text-align:center; font-size:12px;}td{font-size:12px;text-align:center}table .qz{ border:1px solid #ccc; padding:0px; margin:0px;}.ayc{ background:#fff; background-image:none}table td{width:60px; height:60px;}table td input,.axs{ height:60px; width:60px; border:0px; background:url(/jscss/demoimg/201003/zsq.gif) no-repeat center center; color:#ccc; font-size:12px}#zhuangtai{ font-size:16px;}.axz{height:60px; width:60px; border:0px; background:url(/jscss/demoimg/201003/zsq1.gif) no-repeat center center; }.zhuangt{ height:30px; line-height:30px; font-size:12px;}.zhuangt span{ color:red; font-weight:bold;}</style></head><body><h1 style="text-align:center;">獨立鉆石棋</h1><p><div   id="70qarhlowxag"   class="zhuangt">剩余<span id='zhuangtai'>32</span> 個棋子、共走<span id='bushu'>0</span>步</div><script type="text/javascript">var x,y,x1,y1,a1,a2,an=0,qzs=0,str="",bs=0;var xy =new Array() ;xy[0]=new Array(); xy[1]=new Array(); xy[2]=new Array(); xy[3]=new Array();xy[4]=new Array(); xy[5]=new Array(); xy[6]=new Array();function xz(x,y){var a1=document.getElementById("n"+x+y);//alert(x+"-"+y+"-"+x1+"-"+y1+"-"+xy[x,y]);if(an==0 && xy[x][y]==1){a1.className="axz";a2=a1;an=1;x1=x;y1=y;}else if(an==1){if(ks2(x,y,x1,y1)==1){xy[x1][y1]=0;a1.className="axs";xy[x][y]=1;a2.className="ayc";qzs=qzs-1;bs=bs+1;document.getElementById("zhuangtai").innerHTML=qzs;document.getElementById("bushu").innerHTML=bs;}else{a2.className="axs";}an=0;}}//檢測棋子function ks(x,y){if(x<=1 && y<=1 || x<=1 && y>=5 || x>=5 && y<=1 || x>=5 && y>=5 || x==3 && y==3){xs=0;}else{xs=1;}return xs;}function ks2(x,y,x1,y1){xs=0;if(x==x1 && (y-2==y1 || y+2==y1) && xy[x][y]==0){if(y-2==y1 && xy[x][y-1]==1){xs=1;yincang(x,y-1);}else if(y+2==y1 && xy[x][y+1]==1){xs=1;yincang(x,y+1);}}else if(y==y1 && (x-2==x1 || x+2==x1) && xy[x][y]==0){if(x-2==x1 && xy[x-1][y]==1){xs=1;yincang(x-1,y);}else if(x+2==x1 && xy[x+1][y]==1){xs=1;yincang(x+1,y);}}return xs;}function yincang(x,y){xy[x][y]=0;document.getElementById("n"+x+y).className="ayc";}function zb(x,y){for (x=0;x<=6;x++){for (y=0;y<=6;y++){if(ks(x,y)==1){document.getElementById("n"+x+y).className="ayc";}}}document.getElementById("n25").className="axs";}document.write("<table>");for (x=0;x<=6;x++){document.write("<tr>");for (y=0;y<=6;y++){if(ks(x,y)==1 || (x==3 && y==3)){xy[x][y]=1;//str=str+","+x+","+y+"-"+xy[x][y]+"<br>";//alert(x+"-"+y+"-"+x1+"-"+y1+"+xy[x][y]+");document.write("<td class='qz'><input id='n"+x+y+"' type='button'   value=''  onclick='xz("+x+","+y+")'/></td>");}else{document.write("<td></td>");}}document.write("</tr>");}document.write("</table>");document.getElementById("n33").className="ayc";qzs=32;xy[3][3]=0;//document.write(str);</script></body></html>

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